00:01
In this exercise, we have to calculate the momentum of an electron that has the following speed.
00:06
For question a, we have to calculate the momentum for 0 .01 times the speed of light.
00:16
So remember that the relativistic momentum, p is equal to mv times gamma, and gamma is 1 over the square root of 1 minus v squared over c squared.
00:29
Now remember, first of all, that the mass of the electron is equal to 9 .1 times 10 to the minus 31 kilograms.
00:45
Then notice that for v equal to 0 .01 times c, v divided by c is 10 to minus 2, and v squared divided by c squared is 10 to minus 4.
01:02
Meaning that the square root of 1 minus v squared over c squared is the square root of 1 minus 10 to the minus 4, which is approximately 1.
01:18
So instead of using the relativistic formula, i'm just going to use the usual newtonian formula mv to get that the mass of the electron is 9 .1 times 10 to the minus 31 kilograms.
01:31
And the speed is 0 .01 times 3 times 10 to the 8 meters per second.
01:41
So we obtain that p, the momentum, is equal to 2 .73 times 10 to the minus 24 kilograms meters per second.
01:54
Then in question b you have to calculate p for v equal to 0 .5 times speed of light.
02:07
So in this case, we have to include the gamma...