00:01
So this question is asking us to take a look at the idea of ratios and proportions with the idea of molar mass and formula units to figure out the number of particles, anions, and cat ions inside some ionic compounds.
00:14
The very first one is asking to take a look at the idea of 0 .764 grams of cesium iodide and how many cations and anions are inside both.
00:26
So the first thing i have to do is convert that to moles.
00:29
So for every 1 mole of cesium iodide, we have 259 .81 grams of cesium iodide.
00:42
And then we can convert that into a number of particles.
00:45
Well, for every 1 mole of cesium iodide, we have 6 .02 times 10 to the 23rd formula units.
00:57
We'll review that formunes of cesium iodide.
01:01
And then here, we can branch off into two different sets of answers that we can apply every time.
01:11
For every one formula unit of cesium iodide, we have one iodide.
01:25
And then for every one formula unit of cesium iodide, we have one cesium cation.
01:37
So we're doing the same conversions, but at one point we can take a different branch.
01:45
And for the iodides, we have 1 .77 times 10 to the 21st iodide anions.
01:59
And then since it's a one -to -one ratio, we have the same for our cesium cations...