00:01
Okay, well, we're giving a couple of solutions here.
00:04
So let's go ahead and take a look and see what we have for moles to start with, so we can keep track of what's happening.
00:11
So i've got 20 milliliters of our c6, h5, and h2, our amine.
00:23
So i'm going to go ahead and use the density to change milliliters to grams.
00:27
And then i'm going to go ahead and use the molar mass to change grams to moles.
00:31
So our density was given as 1 .022 grams per liter.
00:37
Our molar mass is 93 .14.
00:42
So we'll see that we have 0 .219 moles of our mean here.
00:53
And then they gave us the molarity and the volume of our other solution.
00:57
So 1 .67 molar times its volume in liters will give us the moles.
01:07
So that gives us 0 .5 .85 moles.
01:14
And that's of our hcl.
01:16
And that'll be the same number of moles, right, of our h plus, because that's a strong acid.
01:24
So since we have a weak base and a strong acid, they're going to react with each other.
01:31
So let's go ahead and write the reaction that's going to take place here.
01:38
We'll just come together and form this weak acid.
01:45
And we'll keep track of what's happening here.
01:47
With a little table of initial change and final.
01:53
So to start with, i have 0 .219 moles here and 0 .0585 moles here.
02:02
I haven't made any of this yet.
02:04
The hydrogen ion is our limiting reactant...