00:01
So here we're given a specific reaction where aluminum combines with oxygen gas and hydrogen ions to form aluminum.
00:10
It's three plus four and six water molecules.
00:14
So essentially this is a reaction where we have basically it's a redox reaction.
00:20
So we can break this down into its half reactions.
00:25
So we need essentially charge conservation, same charge and basically, and the same.
00:31
Same number of atoms on both sides.
00:33
So we can see that this reaction satisfies its condition.
00:36
So we're going from a lower oxidation state of zero to a higher oxidation of state of plus three.
00:41
So this reaction is an anode oxidation reaction.
00:45
And on the other hand, we essentially have a reduction reaction on the other side, where we're essentially forming six water molecules.
00:55
And we can see that we have 12 moles of electrons transfer.
00:59
12 moles of electrons given up are given to essentially the reduction reaction.
01:07
And now we essentially can find the values for essentially the reduction potentials in a standard table...