Question
Calculate the standard Gibbs energy of formation of $\mathrm{SO}_{4}^{2-}(\text { ao })$ from $\Delta_{\mathrm{f}} H^{\circ}$ and $\bar{S}^{\circ}$ values in Table C.2.
Step 1
We know that the standard Gibbs energy of formation, ΔGf°, is related to the standard enthalpy of formation, ΔHf°, and the standard molar entropy, S°, by the equation: ΔGf° = ΔHf° - TΔS° Show more…
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For PbI2(s) ⇌ Pb2+(aq) + 2 I-(aq), K = 1.4 × 10^-8 at 25°C and the standard Gibbs energy of formation of PbI2(s) is -173.64 kJ mol^-1. Calculate the standard Gibbs energy of formation of PbI2(aq).
The standard Gibbs free energy of formation is $$ -286.06 \mathrm{~kJ} / \mathrm{mol} \text { for } \mathrm{NaI}(\mathrm{s}),-261.90 \mathrm{~kJ} / \mathrm{mol} \text { for } \mathrm{Na}^{+}(\text {aq }) $$ and $-51.57 \mathrm{~kJ} / \mathrm{mol}$ for $\mathrm{I}^{-}(\mathrm{aq})$ at $25^{\circ} \mathrm{C}$. Calculate $\Delta G^{0}$ for the reaction $$ \mathrm{NaI}(\mathrm{s}) \stackrel{\mathrm{H}_{2} \mathrm{O}}{\longrightarrow} \mathrm{Na}^{+}(\mathrm{aq})+\mathrm{I}^{-}(\mathrm{aq}) $$
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