First, we need to find the equivalent resistance of the circuit. We can see that the 4 kΩ and 2 kΩ resistors are in parallel, so their equivalent resistance is given by:
$R_{eq} = \frac{4 kΩ × 2 kΩ}{4 kΩ + 2 kΩ} = \frac{8 kΩ^2}{6 kΩ} = \frac{4}{3} kΩ$
Show more…