00:01
Okay, so for this first one, let's go ahead and take that shortened hand notation and change it into our two half reactions.
00:08
So zinc is being oxidized to zinc ion, two electrons.
00:15
Our voltage is going to be 0 .762 volts.
00:19
Our cadmium ion is going to be reduced to cadmium metal.
00:26
And that will be negative 0 .402 volts.
00:29
Since the electrons are equal, we'll just add this up to get our overall reaction.
00:37
Sink solid plus cadmium ion gives us cadmium solid plus zinc ion.
00:48
So our overall standard potential, this is our e0, is 0 .360 volts.
00:56
So we'll go ahead and write our expression for the nernst equation over n.
01:04
So you saw that we had two electrons lost and gained.
01:09
So n equals 2.
01:11
So we'll put that over 2.
01:13
And then the ln of, let's see, our concentration of our zinc ion, divided by the concentration of our cadmium ion.
01:23
That's our expression for q.
01:26
So we start plugging it when we know.
01:29
0 .360.
01:31
0 .257 minus, sorry, divided by 2.
01:35
The ln of 0 .5 over 0 .020.
01:44
So this will give us 0 .360 minus 0 .041...