00:01
In this problem, we are given four different scenarios, and we are asked to calculate the ph for each one of the solutions.
00:10
I'm just going to do them each separately.
00:12
Our first solution is 0 .0 .135 molar nitric acid.
00:27
That's our simplest one.
00:29
So this, since it's a strong acid, this equals 0 .00135.
00:37
Molar h plus and to get the ph we simply take a negative log of 0 .00 135 molar equals 2 .870.
01:03
There's our first calculation.
01:07
In our second calculation we are given b 0 .425 grams of perchloric acid in 2 .00 liters of 1 .00 liters of water.
01:32
This one will also be easy.
01:37
First, well i'm going to do it all in one step.
01:40
We're going to figure out our concentration, which will be in moles per liter.
01:46
And to get moles, we're going to take our 0 .425 grams.
01:57
We're going to multiply that by the molar mass, which is 100 .5 grams per mole.
02:08
There's our moles.
02:09
We're going to divide that by 2 .00 liters.
02:15
This equals before rounding 2 .114 times 10 to the minus third molar.
02:23
And we could round that if we wanted to now, but i think i'll wait.
02:36
Our ph will be the negative log of 2 .114 times 10 to the minus 3.
02:43
Let me stick this one in my calculator quick.
02:54
It was 2 .675 for our second scenario.
03:10
Okay, my third one is going to be a dilution...