Question
Calcule la concentración molar de iones $\mathrm{OH}^{-}$de una disolución $0.075 \mathrm{M}$ de etilamina $\left(\mathrm{C}_2 \mathrm{H}_5 \mathrm{NH}_2\right)\left(K_b=6.4 \times\right.$ $10^{-4}$ ). Calcule el $\mathrm{pH}$ de esta disolución.
Step 1
Step 1: Write the chemical equation for the dissociation of ethylamine in water: $\mathrm{C}_2 \mathrm{H}_5 \mathrm{NH}_2 + \mathrm{H}_2 \mathrm{O} \rightleftharpoons \mathrm{C}_2 \mathrm{H}_5 \mathrm{NH}_3^{+} + \mathrm{OH}^{-}$ Show more…
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Calculate the molar concentration of $\mathrm{OH}^{-}$ ions in a $0.075 \mathrm{M}$ solution of ethylamine $\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2} ; \quad K_{b}=\right.$ $6.4 \times 10^{-4}$ ). Calculate the pH of this solution.
Calculate the molar concentration of $\mathrm{OH}^{-}$ ions in a $0.075 \mathrm{M}$ solution of ethylamine $\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2} ; K_{b}=6.4 \times 10^{-4}\right) .$ Calcu- late the $\mathrm{pH}$ of this solution.
Calculate the molar concentration of $\mathrm{OH}^{-}$ in a 0.075 $\mathrm{M}$ solution of ethylamine $\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2} ; K_{b}=6.4 \times 10^{-4}\right) .$ Calculate the pH of this solution.
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