00:01
Okay, so in this problem we are given two reactions for which we know their delta g values, and a third reaction for which we do not know the delta g or the equilibrium constant for that reaction, which is what we want to find.
00:17
So it is very easy to see that from the first two reactions we can combine them to obtain the third reaction.
00:24
Now, on the first reaction we can see that we have hbo2 as a product, whereas on the resulting reaction we want it as a reactant.
00:36
So what we are going to do is we are going to invert the first reaction.
00:41
Keep in mind that when we invert a reaction the delta g value for that reaction changes sign, so it is going to be a positive 70 now.
00:49
What i am going to do now is i am going to erase the first reaction and write down the reverse reaction, so that we can see the final product.
01:03
So we have hbo2.
01:06
I am basically reversing the first reaction.
01:13
And then if we add these two resulting reactions we are going to obtain the product that we are looking for.
01:20
Keep in mind that hb, since it is on both sides, one as a product and one as a reactant, can be cancelled out.
01:28
So with that we are going to obtain the resulting reaction that we are looking for, and the delta g for this new reaction is going to be the sum of the other two...
