Acetylacetone (see Exercise 69, part a), abbreviated acacH, is a bidentate ligand. It loses a proton and coordinates as acac $^{-}$, as shown below: Acetylacetone reacts with an ethanol solution containing a salt of europium to give a compound that is $40.1 \% \mathrm{C}$ and $4.71 \% \mathrm{H}$ by mass. Combustion of $0.286 \mathrm{~g}$ of the compound gives $0.112 \mathrm{~g}$ $\mathrm{Eu}_{2} \mathrm{O}_{3}$. Assuming the compound contains only $\mathrm{C}, \mathrm{H}, \mathrm{O}$, and $\mathrm{Eu}$, determine the formula of the compound formed from the reaction of acetylacetone and the europium salt. (Assume that the compound contains one europium ion.)