00:01
In this problem, we're told that four different octahedrochromium coordination compounds exist, that all of the same oxidation state for chromium, and have water and chloride as ligands and counter ions.
00:15
When one mole of each of the four compounds is dissolved in water, how many moles of silver chloride will precipitate with the excess of silver nitrate? okay, so in thinking about this right now, i believe that this is going to have to be chromium three.
00:40
That's the only one with four different, the only one.
00:45
So chromium four would form five different compounds, five compounds, and chromium two would form three.
01:18
So it has to be chromium three.
01:19
So the compounds are going to be.
01:26
First, we'll have the albchromium.
01:31
We're going to go h2o next.
01:53
And then this will be and counter ions.
02:08
Okay, let's do six with this...