Question
Tetrahedral complexes of $\mathrm{Co}^{2+}$ are quite common. Use $d$ -orbital splitting diagram to rationalize the stability of $\mathrm{Co}^{2+}$ tetrahedral complex ions.
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In a tetrahedral complex, the central metal ion is surrounded by four ligands, which are arranged at the corners of a tetrahedron. Show more…
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Text: Draw a molecular orbital diagram a. Tetrahedral complex (COCl4)2- b. Octahedral complex (Fe(H2O)6)3+
Platinum II typically forms diamagnetic, square-planar complexes. Attempts to make octahedral Pt(II) complexes, even with a rigid multicyclic ligand which would force six nitrogens to bind in an octahedral fashion to Pt(II), have not succeeded even though such "septulchrate" complexes of Co(III) are well known and very stable. Use ligand field diagrams to explain the reluctance of platinum (II) to form octahedral complexes.
The following pairs of complexes have very different electron configurations (high-spin vs. low-spin) and, in certain cases, even different geometries. For each complex, do the following: i) draw the structures and state the geometry, ii) sketch the d-orbital splitting diagram and show the expected occupancy, and iii) explain the differences between the pairs of complexes: a. [Fe(CN)6]3- and [FeCl6]3- b. [Co(NH3)6]2+ and [Co(NH3)6]3+ c. [CoF6]3- and [Co(H2O)6]3+ d. [PdCl4]2- and [NiCl4]2-
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