00:01
We are to give the formula for the following.
00:04
The first one is exarchase, cobot 3, exasperidine, cobalt 3, chloride.
00:23
So exact case means 6, so cobot 3, period in exactase.
00:35
So that's 6, periodine, then chloride, just one chloride, and it's a cobot 3.
00:53
So being cobot 3 means the cobot has to have an oxidation state of plus 3.
01:10
The question does not tell us that it is a cation or it's an an ion.
01:14
So this complex is not an ion.
01:17
So in order to make a cobot to have an oxidation state of plus 3, this chloride will not be in the bracket.
01:24
So it's going to be house side of the bracket.
01:28
And we're going to have exarchase corbates.
01:35
That's fine.
01:36
Cobot 3.
01:37
Peridin is neutral.
01:38
So to have cobot 3, this has to be 3 plus, right? and that means we have to have 3 chlorine canterhyer, or chloride canterhyer.
01:51
Next one is pentamine, iodide, chromium, 3, hyudide.
02:12
So here we have chromium has the method and we have pentaamin that means we have five immune ligand then we have iodine that means hyaline also coordinating to the matter center and it is an iodide compound so hyoid as canter ion.
02:37
So chromium here is plus three we have a minus one already in the bracket so minus 1 already.
02:48
So when the minus 1 cross over is going to be plus 1.
02:51
So we need plus 2 to make it plus 3 to have chromium 3.
02:56
So that means this is going to be 2 because hyadin will be high minus, 2 of it with 2 minus.
03:02
So 2 minus counter hanayon, we need 2 plus counter cauter such that when this i minus comes out, it can turn to plus 1 and then it can then halved the plus two to give the plus three to form the i, to form the chlorochromium 3.
03:21
Okay.
03:21
The next one is tris athlindiamine, nichl2 bromide.
03:46
So it's a nickel two compound.
03:55
And we are told that we have a trace of therine diamine.
03:58
So trees as lindiamine.
04:01
I represent an amine as an en.
04:03
And trees means that we have three of it.
04:07
And that's nickel two and it's bromide.
04:12
Okay.
04:15
So being nickel two, aoline damein is neutral.
04:18
So to have a charge, we need a plus two on this complex cartel.
04:28
So to have a plus 2, we need to make this to be br2 so that br is br minus, so times 2 of it will be minus 2.
04:37
So the counter -cation with a plus 2.
04:40
So that can make nickel to be nickel 2...