00:01
In this question we have been given certain compounds and we need to do their naming.
00:04
So the first compound that we have is n -a2, n -a -2 -o4 whole size.
00:13
Now this is called an oxalate ion.
00:17
So this will be called oxalato in our compound name.
00:23
Since this is our ketion, first we are going to write sodium and then we will write the name of the complex which is our an ion over here, right? so, this is going to be sodium.
00:38
This oxalato is present three times, so this is going to be pris, since this is an organic compound, sodium tris, oxalato, nickelate.
00:53
Now, we need to write the oxidation state of nickel here.
00:58
So this is present in minus two oxidation state.
01:04
This is going to get multiplied by three.
01:06
So in order to cut into.
01:06
Find the oxidation state this is going to be x minus 6 3 into 6 is equal to 2 right with a minus sign this is going to become 6 minus 2 which is 4 right so in the next part we have k2 co -cel4 this is our ket ion so we are going to start the name by this potassium then for this chlorine will have a prefix of tetra since this is present four times so this is going to be potassium tetr chloro cobaltate now chlorine is present in minus 1 oxidation state so x minus 1 into 4 is equal to 2 right so the oxidation of oxidation state of cobalt is 2 over here.
02:22
In the next part we have cu nh3 4 times so4.
02:29
Now this is an amine group and since this is present 4 times this is going to start with a tetra...