00:01
So we have to name the given coordination complexes and first of all we have given ru nh3 whole 5 cl2 positive.
00:14
So here first of all we will name the license, okay, we will start naming from this license so we will maintain the alphabetic order.
00:28
We have two liens here we have ammonia and this amine lysant okay amine lyzant and chloro lyzant so alphabetically a comes first so this will be pantomene okay there are five amine lysance and then we have c l so this is chloro now i have this metal ruthenium so ruthenium okay metal will be written in the last and now i will consider the oxidation state so that is written in the roman number so for this amine lyzant so i have this is neutral lyzant okay so now for cl this has minus 1 charge so overall we will have plus 3 oxidation state and this will be written as third okay so this will be the name now and this is to be noted that we will leave no space between the written name.
01:40
We have fc, cn's whole 6, 4 negative.
01:47
So first of all, we will calculate the oxidation state.
01:50
If i consider the oxidation state for fcbx, then this will be x plus for cn.
01:57
We have minus 1 charts.
01:58
So this will be minus 1 multiplied by 6 is equals to minus 4.
02:02
Overall charge is minus 4.
02:03
So on solving, this will be x is equals to plus 2.
02:08
Okay, so this is the oxidation state.
02:11
So now i have 6 cn here, okay, 6 cn lies and so it will be written as hexa.
02:21
Okay, for 6 we will write hexa prefix sinido.
02:29
And now if we have overall negative charge, okay, then we add 8 prefix to.
02:37
The metal.
02:39
If you have plus charge, we will write the metal name as it is...