00:01
We have to name the complex ions.
00:02
First of all is nicn whole 4 to negative.
00:09
So we will write first of all the lyzand name and then it is followed by the central metal atom name.
00:16
Or we should say central metal ion name.
00:19
So now in this case, first of all we will calculate the oxidation state considering the oxidation state for nickel bx then this will be for cn we have minus 1 charge.
00:31
This will be 4 multiplied by minus 1 is equal to overall charge is minus 2.
00:36
And solving this we will get x is equal to plus 2.
00:39
Okay.
00:40
Now i have 4 cn license.
00:43
So this will be here.
00:47
Tetra.
00:48
Tetra prefix will be used for 4 cn license.
00:52
Then, sinido, tetra cyanido.
00:58
And now i have nickel here.
01:00
Now whenever i have overall minus charge, so in that case we will end the metal name by adding 8 suffix.
01:09
Okay, so this will be neglect and overall oxidation state is second.
01:18
Okay, so this will be the name for this given ion.
01:23
So now for this complex ion, all you have to keep in mind that we will write the license name first, okay? and then we will write the metal line name okay and in case if you have overall minus charge so you will add eight suffix to this okay then b part this oxidation state we calculated here this should be written in the roman number method and now cr nh 3 all 4 cl 2 positive so we have two license here we have a amine lysent and we have chlorolizant.
02:10
So we will consider the alphabetic order.
02:13
So for 4 amine lysense, so we will use prefix tetra.
02:21
Teteramine.
02:25
Then we have 2 chloro lysins.
02:28
So di -chloro.
02:31
Then we have chromium here and this carries overall positive charge.
02:38
So metal iron will be written as chromium...