A compound related to acetylacetone is $1,1,1$ -trifluoroacetylacetone (abbreviated Htfa):
Htfa forms complexes in a manner similar to acetylacetone. (See Exercise 45.) Both $\mathrm{Be}^{2+}$ and $\mathrm{Cu}^{2+}$ form complexes with tfa $^{-}$ having the formula $\mathrm{M}(\mathrm{tfa})_{2}$. Two isomers are formed for each metal complex.
a. The $\mathrm{Be}^{2+}$ complexes are tetrahedral. Draw the two isomers of Be(tfa) $_{2}$. What type of isomerism is exhibited by $\mathrm{Be}(\mathrm{tfa})_{2} ?$
b. The $\mathrm{Cu}^{2+}$ complexes are square planar. Draw the two isomers of $\mathrm{Cu}(\mathrm{tfa})_{2} .$ What type of isomerism is exhibited by $\mathrm{Cu}(\mathrm{tfa})_{2} ?$