Step 1:
First, distribute the fractions within the parentheses:
$$
\frac{3}{4}x - \frac{1}{5}\left(\frac{1}{2}-3x\right) + 1 = \frac{1}{4}\left(\frac{1}{20}x+6\right) - \frac{4}{5}
$$
becomes
$$
\frac{3}{4}x + \frac{1}{10} - \frac{3}{5}x + 1 = \frac{1}{80}x +
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