00:01
Okay, so for this question, we have one liter of water, and they tell us the heat of fusion is 333 grams per joules per gram.
00:09
And they're telling us to calculate how much energy is involved when one liter of water solidifies to ice at zero degrees celsius.
00:18
So the solution is already at one degree, zero degrees celsius.
00:22
And when water freezes, it stays at zero degrees celsius until all water is frozen, then it can decrease in temperature.
00:29
This means that the delta t for this calculation is zero.
00:35
Now the equation that we need to use is q is equal to m, mass, and grams, times by the heat of fusion.
00:43
Right? so in heat of fusion, we see we have jewels and grams, but we don't have any grams of water.
00:48
So we need to calculate grams of water, and we can do that by taking the liters...