Chromium(VI) forms two different oxyanions, the orange dichromate ion $\left(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\right)$ and the yellow chromate ion $\left(\mathrm{CrO}_{4}^{2-}\right) .$ The equilibrium reaction between the two ions is
$$\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons 2 \mathrm{CrO}_{4}^{2-}(a q)+2 \mathrm{H}^{+}(a q)$$
The following pictures show what happens when sodium hydroxide is added to a dichromate solution.
(IMAGE NOT COPY)
Explain what happened.