Chromium(VI) forms two different oxyanions, the orange dichromate ion, $\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}$, and the yellow chromate ion, $\mathrm{CrO}_{4}{ }^{2-}$. The equilibrium reaction between the two ions is
$$\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons 2 \mathrm{CrO}_{4}{ }^{2-}(a q)+2 \mathrm{H}^{+}(a q)$$
The following pictures show what happens when sodium hydroxide is added to a dichromate solution.
Explain what happened.