Circuit Analysis Consider the circuit in the figure.
The currents $I_{1}, I_{2}$ and $I_{3}$ in amperes are given by the
solution of the system of linear equations.
$$\left\{\begin{aligned} 4 I_{1} &+8 I_{3}=2 \\ 2 I_{2}+8 l_{3} &=6 \\ I_{1}+I_{2}-I_{3} &=0 \end{aligned}\right.$$
Use Cramer's Rule to find the three currents.