Question
Committees The number of different committees of 3 students where the 3 students are selected from a class of $n$ students is given by $c(n)=\frac{1}{6} n^{3}-\frac{1}{2} n^{2}+\frac{1}{3} n$. If an art class has 10 students, how many different committees having 3 students can be selected?number of years after 2018. Determine the amount in the account in a) 2019. b) $2033 .$
Step 1
We are also given that the art class has 10 students, so we need to find the number of different committees when $n=10$. Plugging in $n=10$ into the formula, we get: $c(10)=\frac{1}{6}(10)^{3}-\frac{1}{2}(10)^{2}+\frac{1}{3}(10)$ Show more…
Show all steps
Your feedback will help us improve your experience
Hunza Gilgit and 93 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
How many committees of 3 students can be chosen from a class of 20? 8750 6840 1140
6. How many committees of 5 students can be formed from 7 students? a. 21 b. 210 c. 42 7. If C = 15, n = 6 and r = ?
Consider three classes, each consisting of $n$ students. From this group of $3 n$ students, a group of 3 students is to be chosen. (a) How many choices are possible? (b) How many choices are there in which all 3 students are in the same class? (c) How many choices are there in which 2 of the 3 students are in the same class and the other student is in a different class? (d) How many choices are there in which all 3 students are in different classes? (e) Using the results of parts (a) through (d), write a combinatorial identity.
Combinatorial Analysis
Self-Test Problems And Exercises
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD