00:01
This question wants us to compare the oxidation of succinate by nad plus and fad in order to determine why fad is the electron acceptor in this reaction catalyzed by succinate dehydrogenase.
00:13
So the relevant half reactions for the oxidation of succinate by nad is the half reaction of sexinate, which forms fumerate.
00:24
It is the opposite of the equation given in table 18 .1.
00:31
So in this reaction, succinate is being oxidized to form fumarate, two protons, and two electrons, with two electrons being passed, and the standard redox potential for this reaction is negative 0 .03 volts.
01:00
So we can use this half reaction to catalyze the free energy.
01:05
For this half reaction, using this equation, which relates the number of oxygens times faraday's constant times the redox potential to the free energy change.
01:17
So with this equation, and knowing our known variables here, and knowing that faraday's constant is equal to 96 .48 kilojoules per mole, we'll find that the delta g, the change in free energy for this half reaction, is equal to 5 .788 kilojoules per mole.
01:45
The relevant half reaction with nad is the reduction of nad to form nad.
01:59
And in this equation, and this reaction two electrons are carried, and it has a standard redux potential of negative 0 .32 volts.
02:17
So similarly, we can calculate the free energy change for this reaction, for this half reaction of nedh, and we will find it to be equal to 61 .7472 kilojoules per mole.
02:36
So the net reaction for the oxidation of succinate by nad will be given by succinate reacting with nad plus in order to form fumerate a proton and nadh.
03:05
And we can calculate the change in free energy for this overall reaction by summing the change in free energies for for the half reactions, and we will find that the change in free energy for the oxidation of succinate by nad is equal to positive 67 .536 kilojoules per mole, which is a positive delta g, which is an endergonic process, which is not that favorable to occur...