00:03
Okay, for this question, we have succinate dehydrogenase using enzyme bound n -a -d -positive.
00:13
So the reaction will go as succinate leads to fuma rate fum a -r -r -a -r -t -e plus two electrons plus two hydrogen positive, which has reaction energy as 0 .0 -3 -1 boths.
00:41
And the second reaction is nad positive plus two electrons plus two hydrogen positive leads to formation of nadh, which has reaction energy as negative 0 .3 volts.
01:02
So if so, net if nadp positive is electron acceptor.
01:09
So overall energy will be negative 0 .32 minus 0 .031 equals negative 0 .312 equals negative 0 .351 volts.
01:26
This solves the first part of the reaction.
01:29
Moving on to the second part.
01:31
According to the provided data, the value of delta g for nad positive is calculated.
01:40
By electropotential formula.
01:44
The formula stands as delta g0 is equal to negative n f delta e.
01:54
We have delta e already.
01:57
N represents the number of moles of electrons from balanced redox reaction.
02:04
And in this case, n value is 2.
02:07
F stands for faraday current or faraday constant...