Complete and balance each of the following reactions. a. the reaction between sulfur dioxide gas

Complete and balance each of the following reactions. a. the...

Key Concepts

Combination Reactions

Combination reactions, also known as synthesis reactions, occur when two or more reactants combine to form a single, more complex product. This type of reaction is common in the formation of oxides and acids, demonstrating how elemental or simple molecular species interact to create compounds with new properties.

Dehydration Reactions

Dehydration reactions are those in which water is removed from a molecule, often through the action of a strong dehydrating agent such as concentrated acid. In organic chemistry, dehydration reactions can break down larger molecules into simpler substances, a principle commonly illustrated in the conversion of carbohydrates by acid catalysts.

Balancing Chemical Equations

Balancing chemical equations is the process of adjusting the coefficients in a chemical reaction so that the number of atoms of each element is conserved. This reflects the law of conservation of mass, ensuring that no atoms are lost or gained as reactants transform into products.

Stoichiometry

Stoichiometry involves the quantitative relationships between reactants and products in a chemical reaction. It uses the coefficients from balanced equations to calculate how much of each substance is needed or produced, ensuring that the proportions reflect the conservation laws and facilitate efficient reaction planning.

Transcript

00:01 Okay, so the first reaction we want to cover in this problem for part a is the reaction between sulfur dioxide gas and oxygen gas.

00:12 So this question is just asking us to write out the reaction and balance the equation.

00:19 So let's start with our so2, so sulfur dioxide.

00:24 So really the only thing you need to know for the reaction is just know by name what these are.

00:32 Sulfur dioxide is obviously s .o .2 and oxygen gas is o2.

00:38 It's one of the noble gases, so it's o2.

00:49 And then, so this reaction gives us sulfur trioxide.

01:00 It's just basically a, one of the oxygens gets added to the sulfur dioxide and it gets over trioxide, and that's also a gas.

01:12 So the main part of this question is now balancing this equation.

01:18 So once we have a reaction right now, as we do, we want to balance it.

01:21 So to balance it, we just want to make sure that we have the same number of each atom on the left side as we do on the right side.

01:29 You know, it has to be balanced.

01:34 So we have, so let's start by looking at our sulfur.

01:38 We have one sulfur over here and we have one sulfur over here.

01:42 So that is balance.

01:45 Now, if we look at the oxygen, we'll see that we have two oxygens with the sulfur dioxide and two on their own with the oxygen.

01:53 So we have a total of four oxygens on the left side, while we only have three oxygens on the right side.

02:08 So if we want to balance this, we're going to have to find some co -efficient that will allow us to make these oxygens equal on both sides.

02:20 But at the same time, we have to make sure that we are not making the sulfur atoms unequal since we already have a one -to -one ratio on both sides.

02:32 So there are many ways you can think about this and do this.

02:38 One way it's just a kind of eyeball and kind of think about it.

02:41 Well, we can look at, so we have four actions over here and three actions over here.

02:46 How are we going to get the same on those sides? well, we can think about common multiples for one and see what we get there.

03:05 But that's kind of difficult for this equation, just because we have two oxygen as part of this, and we have two as part of this.

03:14 So there's always these extra two that are going to add on.

03:16 So what i actually did to balance this equation is i looked at this.

03:22 In a mathematical sense, if we take the sulfur atoms to be a variable, say x, since these are equal, right, we know that x is something, we can find the coefficient by solving for x if we set up an equation.

03:48 So what i did was i took our two oxygens, right? we have two oxygens.

03:52 I took times x, right? and that's going to be a coefficient, right? we're just going to ignore the sulfur since they're even on both sides.

04:02 So i took 2x, and then i added 2, because we have another two options over here.

04:10 And then set that equal to, well, we know x has to be the same since there's one -to -one's over.

04:18 So this is x again, but there's three auction, and so we have 3x.

04:24 And then, you know, i just did some basic algebra and solved this equation to get 2 equals x.

04:34 And this might not, this isn't going to work for every equation that you want to balance.

04:39 This just works since these sulfur atoms are already balanced, and there's only one other thing to balance here.

04:48 So that's why this worked out nicely.

04:51 But as you can see, this actually works.

04:55 Because if x is 2, that means we got 2 here, and we put a 2 here.

05:04 Then this balances out the equation because we have 2 times 2, which means 4 oxygens plus these 2 so that gets us a total now of 6 oxygens on the left.

05:17 Then we have 2 times 3, which is 6.

05:19 So we have 6 oxygons on the right.

05:21 And since we have a coefficient of 2 in front of both of these things, we have 2...

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