00:01
In this problem, we are asked to complete the following table.
00:04
And the table i've tried to reproduce somewhat here, and i'm going to be sort of switching back and forth.
00:11
So first, let's complete row a.
00:18
In row a, we are given that our h -plus concentration is 7 .5 times 10 to the minus -3 molar.
00:31
We know, and we're going to follow this format for all of our calculations, h plus times oh minus is equal to 1 times 10 to the minus 14th.
00:46
So our oh concentration will be equal to 1 times 10 to the minus 14th divided by our h plus.
01:00
I just want to make a note on this equation.
01:03
I can switch those to depending on what i'm trying, what i'm given.
01:09
So substituting, i get 1 times 10 to the minus 14th divided by 7.
01:18
Times 10 to the minus third.
01:21
I get 1 .33 times 10 to the minus 12th.
01:27
And a two sig figs 1 .3 times 10 to the minus 12th.
01:39
And i'm going to put my first molarity up there.
01:43
Second, we're going to calculate our ph.
01:49
And ph is the negative log of our h -plus concentration, which will be the negative log of 7 .5.
02:10
Times 10 to the minus 3.
02:13
And that will equal 2 .12.
02:16
And that is correct for sigfix.
02:23
Third, let's go with a green.
02:47
And we can see from the ph that this is an acidic solution.
02:57
Okay, line one done.
03:01
Row two, red first.
03:05
And here we were given an oh concentration of 3 .6 times 10 to minus 10.
03:18
So our h plus will be equal to, and we can take, to get our ph, take the negative log of, i'm going to make 2 .78 times 10 to the minus 5th, 4 .56, and 4 .56 plus x.
04:21
14, so x equals 9 .44, and this one will also be acidic.
04:57
Okay, our next batch we are given.
05:02
Ooh, lost my, i got to go see what i'm given.
05:07
8 .25 ph.
05:19
Okay.
05:21
So it'll be easy to get our p -o -h.
05:32
That'll be 5 .75.
05:37
And then we can get our 10 to the negative 8 .25 equals our h plus concentration.
05:55
And that will be 5 .62.
05:59
Times 10 to the minus 9th.
06:03
And then for my oh, i'll just do the old way.
06:14
I could also do this by taking 10 to the negative poh.
06:30
Okay, let's go get these transcribed...