00:07
This question asks us to complete each of the reactions.
00:11
So for part a, we have an alkene here with h2 and platinum.
00:15
This is just going to reduce the alkan, or sorry, the alkenes to an alkan.
00:19
So we will just get butane from this.
00:26
So that is our product for part a.
00:28
In part b, we have a dyeing, so a molecule with two different alkenes in it and two equivalents of cl2.
00:34
And so what this is going to do is we're going to add a cl2 to add a cl2.
00:38
To each of our double bonds.
00:40
And when cl2 adds to a double bond, we put one chlorine on each carbon in the double bond.
00:45
So this product is going to be, look like this.
00:48
We'll have a chlorine on this carbon because that's from the double bond.
00:52
And then chlorine on this carbon, because that was in a double bond.
00:56
So that's our first cl2 equivalent.
00:58
And then this stays the same...