00:01
So we're continuing to look at some reactivity of our aldehydes and ketones where we have the common functional group co and what varies is what is attached to our carbon.
00:12
So r can be carbons or hydrogens, for example.
00:18
So looking at the first example here, so our reaction starts with the protonation of an alkene carbon using a strong acid and this forms a positively charged oxygen atom as a result.
00:29
So our nucleophilic attack of our benzile alcohol, followed by a proton transfer within the molecule, produces our product, which looks as follows.
00:43
So we have our six -membered ring, another oxygen atom, followed by our phenyl.
00:52
So in our next reaction, we have the protonation of our carbonile group using the strong acid.
00:58
So then our hydroxyl group will react with the protonated carbonyl group within our molecule to form a protonated semi -acetyl now.
01:06
And then following this, we lose the proton to a bronzed base.
01:10
That can be any generic base.
01:11
So then our semi -acetyl is protonated by a strong acid again, followed by the dehydration, loss of water, and formation of an oxonium cation.
01:20
So finally, what we see is methanol react with the oxonium ion to form a protonated acetile.
01:26
And then after this, we have the deprotonation by another bronsted base to give the final product.
01:32
Now, our final product looks as such.
01:34
So i've just read out a verbal mechanism.
01:39
I'm not drawing out the full mechanism just to save us time.
01:44
However, if you follow what i've said in terms of i've listed all the groups, what we need, what is attacking, what is being changed.
01:50
You will be able to draw out the mechanism should you need it, but we're just looking at the product here...