00:02
To complete the following table, some formulas have to be used.
00:07
Let me write those formula in a group.
00:11
P .h plus p .o .h is equal to 14.
00:18
Ph is equal to negative log of concentration of h positive, while p .o .h is equal to negative log of concentration of oh negative ions.
00:35
We mark this as number 1, number 2 equation, number 3, and number 4, let me write it, it will be h positive, oh negative, will be equal to kw, equal to 1, multiplied with 10 -2 power negative 14.
00:59
This will be equation number 4.
01:03
These are all the equation which will be required to solve the equation.
01:13
Moving to the second part, for the first row, we have to calculate the concentration of oh negative ion from h -positive ion.
01:23
Using the formula number 4, concentration of oh -negative ion will be equal to 1 multiplied with 10 -0 -0 -19 -14, divided by the concentration of h -positive, which is 7 .5, 10 -rase to 1 -9 -3.
01:42
Oh concentration is 1 .33 multiplied with 10 raised to 1 negative 12.
01:50
Now we calculate the ph using equation number 2...