Question
Compton used photons of wavelength $0.0711 \mathrm{nm}$(a) What is the energy of these photons? (b) What is the wavelength of the photons scattered at an angle of $180^{\circ}$ (backscattering case)? (c) What is the energy of the backscattered photons? (d) What is the recoil energy of the electrons in this case?
Step 1
Substituting the given values, we get \[E = \frac{6.626 \times 10^{-34} \, \text{J s} \times 3 \times 10^8 \, \text{m/s}}{0.0711 \times 10^{-9} \, \text{m}} = 17.4 \times 10^{3} \, \text{eV}.\] Show more…
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Compton used photons of wavelength $0.0711 \mathrm{nm}$. ( $a$ ) What is the energy of these photons? $(b)$ What is the wavelength of the photons scattered at $\theta=180^{\circ} ?(c)$ What is the energy of the photons scattered at $\theta=180^{\circ} ?(d)$ What is the recoil energy of the electrons if $\theta=180^{\circ} ?$
Compton used photons of wavelength $0.0711 \mathrm{nm} .$ a) What is the wavelength of the photons scattered at $\theta=180 .$ ? b) What is energy of these photons? c) If the target were a proton and not an electron, how would your answer in (a) change?
Compton used photons of wavelength $0.0711 \mathrm{nm}$ a) What is the wavelength of the photons scattered at $\theta=180 .^{\circ} ?$ b) What is energy of these photons? c) If the target were a proton and not an electron, how would your answer to part (a) change?
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