00:02
In this question, we are asked to consider a cylindrical capacitor.
00:06
Okay, so this is how the cylindrical capacitor look like.
00:14
We have got inner cylinder and outer cylinder.
00:21
So we are given that the outer radius is r and then the difference is d.
00:30
We want to find the capacitance when the d is much less than r okay so and explain why the limits make sense okay so to do this first we need the capacitance for cylindrical capacitor so c is equal to 2 pi x .0 .l divided by natural lot of r2 divided by r1 okay r2 is the outer radius r1 the inner radius.
01:06
So r2 equals to r1 equals to r minus d.
01:13
Okay, so we will do something to the denominator first.
01:18
Okay, long r2 over r1 is equal to long r divided by r minus d.
01:26
Okay, i'm going to invert.
01:29
So i have, by putting a negative side, i can flip the fraction inside the natural log function and then i get natural log of 1 minus d over r okay then for d much much less than r we have d over r much much less than 1 okay so along 1 plus x is equal to x when x is much less than 1 so we have negative long of 1 minus d over r is approximately equal to negative times negative d over r which is d over r when d is much less than r so c is equal to 2 pi epsilon 0l divide by natural log of r over r minus d and then this is when r is when d is much much less than r we get 2 pi epsilon 0x0 .l divided d...