00:01
In this question, we have a metre stick within a reference frame called f.
00:06
It lies in the xy plane, making an angle of 37 degrees within the x axis.
00:11
The reference frame f moves with a constant velocity v parallel to the x axis of another reference frame x prime.
00:18
We want to find the meter stick's velocity measured in the f prime frame at an angle of 45 degrees to the x axis, and we want to find the length of the meter stick in f prime under these conditions.
00:30
We know that the length is equal to the proper length over gamma, where gamma is the lorentz factor and is equal to 1 over the square root of 1 minus v squared over c squared.
00:43
So as the object is moving along the x axis, this y component will not change, but there will be a change in the x component as a result of this equation.
00:53
So what we need to do is we need to know that both of the y components are the same in both reference frames.
00:59
So, ly is equal to ly prime.
01:06
And as a result, l sine theta is equal to l prime, sine theta prime.
01:20
And now we want to look at the x coordinate.
01:23
So we know that the coordinate in the x prime reference frame is equal to l prime cos theta prime.
01:33
And from the above expression, we can see that l prime is equal to l sine theta over sine theta prime.
01:46
So we can substitute this into here.
01:49
And we can say that lx prime is equal to l sine theta over sine theta prime multiplied by cos theta prime...