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Consider a satellite orbiting at an altitude of $x$ mi above the Earth. The distance $d$ from the satellite to the horizon and the length $s$ of the corresponding are of the Earth are shown in the diagram.(IMAGE CAN'T COPY)To find the distance $d$ we use the formula $d=\sqrt{2 r x+x^{2}} \cdot(\mathrm{a})$ Showhow this formula was developed using the Pythagorean theorem. (b) Find a formula for the angle $\theta$ in terms of $r$ and $x,$ then a formula for the are length $s$
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We can write this as $c^{2}=a^{2}+b^{2}$. Show more…
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Consider a satellite orbiting at an altitude of $x$ mi above the Earth. The distance $d$ from the satellite to the horizon and the length $s$ of the corresponding are of the Earth are shown in the diagram. (IMAGE CAN'T COPY) If the Earth has a radius of 3960 mi and the satellite is orbiting at an altitude of $150 \mathrm{mi},$ (a) what is the measure of angle $\theta ?$ (b) how much longer is $d$ than $s ?$
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Scientists and engineers often use polar equations to model the motion of satellites in Earth's orbit. Let's consider a satellite whose orbit is modeled by the equation r = 22800/(4 - cos(θ)), where r is the distance in miles between the satellite and the center of the Earth, and θ is the angle shown in the following figure. a) For what angle θ is the satellite closest to Earth? b) Find the height of the satellite above the Earth's surface for this value of θ.
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