00:01
In this exercise, we have a molecule represented in the figure by this blue ball that has a radius r and a charge q.
00:14
And the molecule is moving in a fluid.
00:18
So it experiences a drag force that is equal to a constant d times its radius r times the speed v of the molecule.
00:32
Through the fluid, and it's also subject to an electric field that has a magnitude e.
00:41
And the situation is such that the electric force generated by the electric field is equal in magnitude, but opposite in direction, to the drag force exerted by the fluid on the molecule.
01:03
And we want to show that the distance traveled by the molecule in a time delta t is equal to q times e divided by dr times delta t.
01:22
Okay, so notice that the two forces, there are only two forces acting on the molecule.
01:30
They are the electric force, fe.
01:32
Notice that the electric force is equal to q times the electric field.
01:42
And we also have the direct force that points in the opposite direction.
01:48
And we have the information that the electric force is equal to minus the direct force.
01:59
Okay.
01:59
This means that the sum of the forces on the molecule is zero.
02:07
So the net force, fn, is zero on the molecule...