00:01
I'm going to begin by drawing active figure 33 .23.
00:07
Just like this.
00:09
There's a resistor up here.
00:11
Whoops, what did i just do? got the power supply there.
00:20
Got a capacitor.
00:23
And we're measuring the voltage across the capacitor.
00:32
All right.
00:37
So we're going to find the ratio of v out to vn, delta v out to delta vn.
00:47
And r is here and c is here.
00:52
So i'm going to begin by calculating the impedance, which is the square root of r squared plus 1 over omega c squared.
01:06
The current is delta vn over z, and delta v out is going to be i, times x sub c, which is 1 over omega c.
01:30
And so putting these three equations together, i, delta vn over z, but z is r squared plus 1 over omega c squared.
01:51
And then i have to multiply that by 1 over omega c.
01:57
All right.
02:01
Just rearranging then, delta v out over delta vn is one over omega -c square root of r squared plus one over omega -c squared.
02:32
Now, can i simplify that more? and i think i can.
02:36
Let's try it.
02:46
So putting the omega -c in the inside, that would be omega -c -r, all of them squared, plus one...