00:03
This is the answer to chapter 15, problem number 55 from the smith organic chemistry textbook.
00:11
And this problem asks us to consider this bromination reaction of turputane.
00:20
And we're asked quite a bit about this reaction.
00:25
And so for part a, we're asked to calculate the delta h -naught by using the bond dissociation energies in table 6 .2.
00:36
Okay, and so i've drawn the reaction out here.
00:40
So we need to look at what's happening.
00:43
So this is a ch bond broken.
00:50
This is a br -br bond broken.
00:58
And so from that table 6 .2, to break a ch bond is going to cost 381.
01:11
Kilojoules per mole to break a bromine bromine bond is going to cost 192 kilojoules per mole and so when we add those together the left side of this reaction is going to require 573 kilojoules per mole so then looking at the right side of this reaction these are bonds being formed so here we have a carbon bromine bond formed.
01:51
And so that is going to release 272 kilojoules per mole.
02:00
And here we have a hydrogen bromine bond formed.
02:07
And that is going to release 368 kilojoules per mole.
02:17
And so our total energy released on the right side is going to be negative 6004.
02:24
40 kilojoules per mole.
02:31
And when we add those values together, what we get is that the delta h0 for this reaction is going to be negative 67 kilojoules per mole.
02:51
Okay.
02:53
So this is an exothermic reaction.
02:56
Okay.
02:56
So negative 67 kilojoules per mole.
02:59
All right.
02:59
So that's part a.
03:01
So for part b, we are asked to draw a stepwise mechanism for the reaction, including all the steps.
03:12
Okay.
03:13
So this is a free radical process.
03:16
And so we're going to start with an initiation step.
03:20
So that's what the i is for, eye for initiation.
03:24
And so the first thing that's going to happen is that our bromine -bromine bond is going to break when we heat this.
03:34
And so we will get two, oops, we will get two bromine radicals.
03:59
Okay, so there's our initiation step.
04:03
Propagation is going to be two steps.
04:10
And so first, what will happen is this.
04:37
So the radical here will form a new bond.
04:42
So after this step, we'll have this with the radical on the carbon here.
05:02
And we'll also have some hbr.
05:09
Okay, and then our second part of the propagation step is going to be the carbon radical that we just formed.
05:20
It's going to react with an equivalent of bromine gas.
05:30
Or liquid bromine, as the temperature may dictate.
05:39
So like this, they'll form a new bond.
05:45
We'll regenerate a bromine radical here.
05:49
And so after this step, we get our brominated product.
06:01
And as i said, we regenerate a bromine radical here...