00:01
In this problem, we've got a lot of stuff to do.
00:03
So i've given everything that i need to give here.
00:05
And for part a, we're asked to calculate delta g.
00:13
And we're going to use delta g equals negative r t times the ln of k.
00:25
Ok.
00:26
Delta g will equal negative r.
00:32
Let's use 8 .314 j over kmol.
00:46
T is i believe 298 yes and the ln of 0 .090.
00:59
0.
01:02
Okay negative 8 .314 times 298 times ln 298.
01:12
Enter and i get, oh i entered 28.
01:25
8 .314.
01:26
I thought my number looked stupid but i entered 28 instead of 298.
01:32
My ln of 0 .09 and i get 5 ,966 joules times 1 ,000 joules per kilojoule will equal, which i go to to sig figs here.
01:52
I think i'll go to three sig figs, two sig figs, so i'm going to go to 6 .0 kilojoules and that will be, since i didn't cancel out any moles, i'll go to moles.
02:13
Let's go to part b.
02:15
He says use bond energies to estimate delta h.
02:32
Okay, that won't be too hard.
02:38
So i'm just going to quickly jot down h2o has two ho bonds plus cl2o has two clo bonds.
02:55
And that would produce 2 hocl will be hocl will be 2 ho and 2 ocl.
03:10
So for bond energies are equal on each side so my delta h would equal zero.
03:23
That was weird.
03:28
Now let's do c.
03:39
Use their parts from a and b to find delta s.
03:51
So a was 6 kilojoules and from b delta h equals 0.
04:14
So i will have 6 kilojoules equals 0 plus 298.
04:22
Can i assume 298? solving for s i will get 6 divided by 298 would be 0 .020 kilojoules per mole k and then if i take 0 .020 kilojoules per mole k times 1000 whoops joules per mole i'll get 20 and we put decimal right there joules per mole k.
05:38
20 joules per mole k.
05:40
Sounds good to me.
05:42
Was that negative 20? i think yes.
05:51
Let me get back up here.
06:03
This will be negative because this should have been a minus.
06:09
There we go.
06:14
There.
06:15
Now let's do d.
06:21
D says estimate for, let's think, looking at my reaction, hocl.
07:18
Okay, got it.
07:19
I was looking at the wrong substance.
07:21
Okay, so losing my reaction, i'm just going to jot this down again.
07:26
This is going to be zero for this one.
07:31
Plus cl2o is, cl2o was 80 .3.
07:39
So, and that yields hocl times 2.
07:46
So i will have for my delta h, which we said was equal to 0, will equal 2 times x minus 1 times 0 plus 1 times 80 .3.
08:08
Okay, so this will give me 80 .3 equals 2xx equals, where's my, hang on for a second here.
08:55
What is my delta h? oh, that's water.
09:00
This is water...