00:01
All right, so we've got a couple of functions, f and g.
00:04
And the first couple problems aren't too bad.
00:06
So we're going to just find the composition.
00:09
So that means we're taking f of g.
00:13
So we're putting in this thing for you.
00:16
So we're going to get x to the p over q to the power of q.
00:20
Because that thing goes in for you.
00:23
And now exponent rule says the exponents multiply, so that's x to the p like they wanted.
00:28
Okay.
00:29
And now, if we look at this thing, that's the expression for the chain rule, right? that's the derivative of f of whatever's inside times the derivative of the inside.
00:37
So the derivative of that must be the derivative of x to the p, and that's an easy power rule.
00:42
That's p times x the p minus one.
00:46
Okay, and now part c is the one that's worded kind of weirdly.
00:49
They want you to find a power rule for x to the p over q using what you got in part b.
00:56
So what does that mean? they want you to find a rule for taking the derivative of x the p over q, which in fact is g of x.
01:05
So really we're looking for this.
01:09
Well, we know what the whole thing is.
01:11
So really, if we could just find this highlighted thing, we'd be good.
01:15
Okay.
01:16
But what is that? well, f of u is that...