00:01
We have been provided in the given question a reaction in which x2 gets converted into 2x.
00:10
Basically, we are breaking the x2 molecule into 2x atoms.
00:14
And for this, we have to answer what will be the delta h.
00:19
Okay, that has been asked in the given question.
00:23
We have been provided first of all, initial pressure of our x2 to be 7 .15.
00:31
Tor okay and we have been provided pressure of x at equilibrium is equal to 103 tor okay these are at 298 kelvin and further we have been provided initial pressure is equals to 748 thor and pressure of x at itlobrium is equal to 532 thor and these are provided at 755 kelvin.
01:18
So to find the delta as we will need to find what is the value of equilibrium constant at both the two temperatures.
01:26
So we know that first of all if we see the reaction x2 get converted into 2x if its initial pressure is p .i.
01:36
And final becomes p .i minus alpha.
01:39
So this will be equals to 2 alpha.
01:41
Okay this will be equal to two alpha and we have been provided the value of two alpha for 298 kelvin okay for 298 kelvin over two alpha is equal to one zero three so alpha will be one zero three by two now with the help of this we can calculate the final pressure of x2 so that will be pi minus a alpha so our pi is 748 minus alpha so our pi is 748 minus alpha that is 1 .3 2 so this will come out to be 703 .5 thor.
02:17
Okay and equilibrium constant for this type of reaction is equals to x to the pressure of x to the power 2 divided by pressure of x2.
02:29
Okay, so over k1 that is the equilibrium constant at 298 kelvin, will come out to 103 whole square.
02:38
Okay, see how px pressure is 103.
02:42
So, 103 whole square divided by px2 final, which over which came out to be 703 .5.
02:49
So our equilibrium constant at 298 kelvin will come out to be 15 .08.
02:56
Okay.
02:57
Now our k2 at 755 kelvin, we can calculate using the same method...