Consider two conducting spheres with radii $R_{1}$ and $R_{2}$ They are separated by a distance much greater than either radius. A total charge $Q$ is shared between the spheres, subject to the condition that the electric potential energy of the system has the smallest possible value. The total charge $Q$ is equal to $q_{1}+q_{2},$ where $q_{1}$ represents the charge on the first sphere and $q_{2}$ the charge on the second. Because the spheres are very far apart, you can assume that the charge of each is uniformly distributed over its surface. You may use the result of Problem $41 .$ (a) Determine the values of $q_{1}$ and $q_{2}$ in terms of $Q, R_{1}$ and $R_{2} .$ (b) Show that the potential difference between the spheres is zero. (We saw in Chapter 25 that two conductors joined by a conducting wire will be at the same potential in a static situation. This problem illustrates the general principle that static charge on a conductor will distribute itself so that the electric potential energy of the system is a minimum.)