Construct a spreadsheet that can be used to determine the boiling temperature of a liquid in an evaporator as it is being concentrated. The boiling point of a liquid is the temperature at which the vapor pressure equals the atmospheric pressure. A solution will exhibit a boiling point rise because the solute will lower the water activity resulting in a higher temperature to be reached before boiling occurs. The vapor pressure of water $\left(\mathrm{P}^0\right)$ as a function of temperature is expressed by the following equation:
$$
\ln \left(\mathrm{P}^0\right)=\left(-\frac{H}{R}\right)\left(\frac{1}{T}\right)+C
$$
where $\mathrm{P}^0$ is the vapor pressure in kilopascals, $\mathrm{H} / \mathrm{R}$ is the ratio of the latent heat of vaporization and the gas constant, $\mathrm{C}$ is a constant, and $\mathrm{T}$ is the absolute temperature in degrees Kelvin. The value for $H / R$ is 4950 and $C$ is 17.86 .
Atmospheric pressure is 101 kilopascals. The vapor pressure of a solution is $\mathrm{P}=\mathrm{a}_{\mathrm{w}} \mathrm{P}^0$. The water activity $\left(\mathrm{a}_{\mathrm{w}}\right)$ is given by:
$$
\log _{10}\left(\frac{a_w}{f_1}\right)=-k\left(1-f_1\right)^2
$$
$f_1$ is the mole fraction of water and is calculated by:
$$
f_1=\frac{\left(1-x_1\right) / 18}{\left(1-x_1\right) / 18+x_1 / M_1}
$$
$x_1$ is the mass fraction of solute. Assume the solute is only sucrose with a molecular weight $\left(\mathrm{M}_1\right)$ of 342 and a $\mathrm{k}$ value of 2.7 . Have the program display the value of the boiling point when the sucrose concentration is $20 \%$ and at increasing concentrations in $5 \%$ intervals to a final concentration of $60 \%$.