In the dehydration of diced potatoes, the following weights were recorded at various times in the process when dehydration rate was the slowest.
$\mathrm{t}=6$ hours from start of drying: weight $=2350 \mathrm{~g}$
$\mathrm{t}=8$ hours from start of drying: weight is $2275 \mathrm{~g}$; moisture content $=15.6 \%$.
In this range of moisture content, the drying rate is proportional to the moisture content, expressed in mathematical form as follows:
$$
-\frac{\mathrm{dW}}{\mathrm{dt}}=\mathrm{kW}
$$
$\mathrm{W}$ is the moisture content in $\mathrm{g}$ water/g dry matter, and $\mathrm{k}$ is a constant.
(a) Derive an equation for the moisture content, W, as a function of time, $t$, which satisfies the experimental conditions given above.
(b) How long would it take for a product to be dehydrated from $22.5 \%$ to $12.5 \%$ moisture?
$$
\frac{\mathrm{N}_0}{\mathrm{~N}}=\frac{\mathrm{R}^2 \overline{\mathrm{V}}}{2}\left[\frac{1}{\int_0^{\mathrm{R}} \mathrm{rV}_{\mathrm{r}}[10]^{-\mathrm{L} /(\mathrm{V}, \mathrm{D}) \mathrm{dr}}}\right]
$$