Question
Determine the slope of the following functions:$$\begin{array}{cl}f(x)=2 x^4-3 x^2+7=0 & \text { at } x=2 \\x y=(0.5 x+3)(x+2) & \text { at } x=1\end{array}$$
Step 1
Taking the derivative of $f(x)$, we get: $$f'(x) = 8x^3 - 6x$$ Evaluating $f'(x)$ at $x=2$, we have: $$f'(2) = 8(2)^3 - 6(2) = 64 - 12 = 52$$ Show more…
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