00:01
Okay, so for this question, they want us to calculate how much nitric acid is needed to fertilize, to make 5 times 10 to 3 kilograms of ammonium nitrate.
00:13
So they gave us this equation, nh3 plus hno3 yields ammonium nitrate.
00:25
So we want to produce 5 ,000 kilograms of ammonium nitrate.
00:35
So let's see how much hno3 we need.
00:38
So let's convert this kilograms to grams.
00:39
We have one kilogram is equal to 1 ,000 grams.
00:49
So one mo of nh4, n .h4, n .o3 is equal to 80 grams.
00:59
Now let's get to the mole -to -mo ratio.
01:00
We have one more of nh4, n -3, and we have one more of hno3.
01:04
So one mo of nh4 -3 is produced from one moe.
01:13
Of hno3 and one mole of hno3 is 63 grams now so we were trying to calculate how much hno3 is needed so let's look at the units we have kilograms cancels out kilograms grams cancels out grams mows of h4 and 03 cancels out moles of hno3 moles of hno3 canceles out moles of hno3 and we left with grams of hno3 so we set this up correctly and once we plug that into the calculator, we should get 3937500 grams.
01:56
So this is the amount of hn03 that is needed...