00:01
So we want to figure out what angular speed is necessary to produce the spin angular momentum given.
00:07
So the moment of inertia for the sphere, for treating it like a sphere, i, is equal to two -fifths times the mass times the radius squared.
00:15
And the spin -angular momentum, s, is equal to the moment of inertia times the angular velocity omega.
00:21
So for a, we can rearrange to solve for omega and then plug in the values for s and i that we're given.
00:26
So what we have is the square root of three -fourths times h -bar, planks constant, divided by a moment of inertia, which is two -fifths times the mass times the radius squared.
00:51
So since we know all these values, we can simply plug them in.
00:55
H -bar, of course, is 1 .055 times 10 to the minus 34 joules seconds...