00:01
So for this problem, we are going to consider an electron using a classical model of the electron as a particle, orbiting around the nucleus.
00:15
So trinant classically, we have a radius, we're told, 1 times 10 to the minus 17 meters.
00:23
And we want to know what angular velocity omega will give.
00:30
An angular momentum l that is, we're told, three quarters, square out of three quarters times h bar.
00:46
So we want an equation that uses the radius, the angular momentum, and omega.
00:57
So the equation comes to mind is that l is i omega and the less i is the moment of inertia.
01:07
And we're considering the like, electron is a little sphere so we can use i is two -fiths mr squared and we can rearrange this equation then because l is something that we're given to get this as an equation for omega so we have five halves l divided by mr squared and this m here is of course the mass of the electron so you can just plug in l is three quarters h -bar and then we can plug in numbers and see what we get for answer for omega.
02:10
We can use, you can look up h -bar, which is the unit of action, jewel, seconds, and then one over the mass of the electron, and we'll use kilograms to be consistent with jewels, and then adding over here the radius...