Determine the behavior of Newton's method applied to (a) $f_{1}(x)=\frac{1}{5}(8 x-3)$ (b) $f_{2}(x)=\frac{1}{5}(16 x-3),$ (c) $f_{3}(x)=$ $\frac{1}{5}(32 x-3) ;(d) f(x) \quad$ when $\quad f(x)=f_{1}(x)$ if $\frac{1}{2} < x < 1$ $f(x)=f_{2}(x)$ if $\frac{1}{4} < x \leq \frac{1}{2}, f(x)=f_{3}(x)$ if $\frac{1}{8} < x \leq \frac{1}{4}$ and so on, with $x_{0}=\frac{3}{4} .$ Does Newton's method converge to a zero of $f ?$ (See Peter Horton's article in the December 2007 issue of Mathematics Magazine.)