Applying Newton's method to $x^{2}-x-1=0,$ show that (a) if $x_{0}=\frac{3}{2}, x_{1}=\frac{13}{8} ;$ (b) if $x_{0}=\frac{5}{3}, x_{1}=\frac{34}{21}$ (c) if $x_{0}=\frac{8}{5}$ $x_{1}=\frac{89}{55} ;$ (d) The Fibonacci sequence is defined by $F_{1}=1$ $F_{2}=1, F_{3}=2, F_{4}=3$ and $F_{n}=F_{n-1}+F_{n-2}$ for $n \geq 3$ Write each number in parts $(\mathrm{a})-(\mathrm{c})$ as a ratio of Fibonacci numbers. Fill in the subscripts $m$ and $k$ in the following: If $x_{0}=\frac{F_{n+1}}{F_{n}},$ then $x_{1}=\frac{F_{m}}{F_{k}}$ (e) Assuming that Newton's method converges from $x_{0}=\frac{3}{2},$ determine $\lim _{n \rightarrow \infty} \frac{F_{n+1}}{F_{n}}$.